sexta-feira, 6 de setembro de 2013
OTHER QUICK RULES
OTHER QUICK RULES
I will present these rules just to show how my
research provided various possibilities to the creation of numerous quick rules
for divisibility by 7.
Practice turns quick and easy the application
of my rules. At first, as any new knowledge, it may look somehow complicated. Knowing
the multiplication table of seven and having some skill with mental
calculations are the requirements to apply my rules.
Remember that, without success, researchers
have been trying to create a real rule of divisibility by 7 since the beginning
of the first millennium (Talmud) according to the History Of Number Theory.
When I say real rule I refer to a rule that fits into the definition of
divisibility rule according to Wikipedia:
“A divisibility rule is a shorthand way of determining whether a given number is
divisible by a fixed divisor without performing the division, usually by
examining its digits.”
I think that I presented my best rules in my
previous posts and that the explanations of why they work are enough to understand
the “why they work” of the next rules. Therefore, I will present only the respective
algorithm and some numerical examples. If necessary, I will highlight important
details.
Rule 1
N = abc,def → abxc, def
R = ─ de’ mod 7 + x;
if 7|R then 7|N
─ 94 mod 7 + 5 + 13 = 22; R = ─
22 mod 7 + 4 = 10; 7Ɨ10 and 7ƗN
Remainder: (R mod 7 . 4) mod 7; (10 . 4)
mod 7 ≡ 5 = r (remainder of the division N/7)
Rule 2
N = abc.def → aybc, dyef
─ bc mod 7 + a + y + ef; R = ─ ef’ mod 7 + d +
y. if 7|R then 7|N
─ 46 mod 7 + 9 + 1 + 32 = 45; ─ 45 mod 7 + 1 +
4 = 9; 7Ɨ9 and 7ƗN
Remainder: ─ R mod 7 ≡ r; ─ 9 mod
7 ≡ 5 = r (remainder of N/7)
The algorithm must be repeated until the last
period is reached. It uses repetitively the multipliers 546 to each period of
N. It is easy to extend its application to more extensive numbers.
Rule 3
N = a,bcd
(─ cd mod 7) . 3 + b → ab’; if 7|ab’ then 7|N
N = 946,132
[(─ 32 mod 7) . 3 + 1 ] mod 7 = b’ = 3 → 9463
[(─ 63 mod 7) . 3 +4 = b‘ = 4 → 94; 7Ɨ94 and
7ƗN
r = (94 mod 7 . 4) mod 7 ≡ 5 (remainder of N/7)
Regarding larger numbers the algorithm must be
applied until the leftmost digit is reached.
The procedure to determine the remainder is the
same of a previous rule, already presented, that works with pairs of digits.
Rule 4
N = a,bcd → a,bycd
─ (a + b + y) mod 7 + cd
N = 946,132; 9426132 → 6732 → 67032
─ (9 + 4 + 2) mod 7 + 61 = 67
─ ( 6 + 7 + 0) mod 7 + 32 = 33; 7Ɨ33 and 7ƗN
r = 33 mod 7 = 5 (remainder of the division
N/7)
The algorithm must be applied repetitively to
four digits each time until the last digit is reached.
The multipliers applied are: 6231. To reach
this conclusion it is necessary some reasoning.
Rule 5
N = a,bcd → a,bxcd
[─ (x + c + d) mod 7 + a] mod 7
This algorithm must be applied from right to
left. In each application, the last two digits must be eliminated.
N = 946,132; 61632
[─ ( 6 + 3 + 2 ) mod 7 + 6] mod 7 = 2 → 9421 → 94421
[─ (4 + 2 + 1 ) mod 7 + 9] mod 7 ≡ 2 → 24; 7Ɨ24
and 7ƗN
r = (24 mod 7 . 4) mod 7 ≡ 5 = r (remainder of
N/7)
The procedure to determine the remainder is the
same of a previous rule, already presented, that works with pairs of digits.
CONCLUSION
After I deciphered Pascal's criterion of
divisibility by seven it became very easy to create quick rules of divisibility
by seven. Of course, there are many other rules that I might present, but I
think that the rules already presented are enough to illustrate my discoveries.
In my next post I will comment some feedbacks I
received from professional experts.
Assinar:
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