sábado, 31 de agosto de 2013
THE CREATION OF THE FIRST "MOURA VELHO RULE"
HOW I CREATED MY FIRST RULE OF DIVISIBILITY BY
7
I started researching divisibility by 7 in the
beginning of the 1990’s. It took me a long time to reach my best results. In 2005
I created my first method of divisibility by 7 and without noticing it I
created the first rule of divisibility by 7 of the History of Number Theory that
fits the definition of divisibility rule according to Wikipedia:
“… a shorthand way of determining whether a
given number is divisible by a fixed divisor without performing the division,
usually by examining its digits”.
After my
first rule, I created various other rules that are quick and accurate.
From now on, I will summarize the steps I
followed to create my first rule. There were various lapses of time between the
steps, some shorter some longer.
First step:
N = ab; insert “x” before “a” in a way that
7|xa → xab; S = x + a +b
If 7|N then 7|S; if 7ƗN then S mod 7 ≡ r
(remainder of ab/7)
N = 42 → 142 → S = 1 + 4 + 2 = 7; N =
96 → 496 → S = 4 + 9 + 6 = 19; 19 mod 7 ≡ 5 ≡ r
Second step:
N = bc; insert “y” after “c” in a way that 7|cy
→ bcy; S = b + c + y
If 7|N then 7|S; if 7ƗN then S mod 7 ≡ 5r (5
times the remainder of bc/7)
Third step:
N = abc; insert “x” before “a” and “y” after
“c” according to the previous steps:
xabcy; S = x + a + b + c + y
If 7|N then 7|S; if 7ƗN then S mod 7 ≡ 5r mod 7
(5 times the remainder of N/7)
Fourth step:
N = abc,def
After applying the three initial steps to each
period add ─ S1 mod 7 to S2:
S1 = x + a + b + c + y and S2
= x + d + e + f + y
In the passage of one period to another, the
previous sum must be converted to its additive inverse modulo 7 and added
to the next sum till the rightmost period is reached.
─ S1 mod 7 + S2 (two
periods)
─ ( ─ S1 mod 7 + S2 ) mod
7 + S3 (three periods)
The repetitive and cumulative application of
the additive inverse mod 7 results in an alternation of the signs plus and
minus regarding each sum performed.
Example:
N = 26,965,466
First period: 263; 2 + 6 + 3 = 11; ─ 11
mod 7 ≡ “3” (this result will be added to the digits of the second period)
Second period: ”3” 49656; 3 + 4 + 9 + 6 + 5 + 6 = 33; ─ 33 mod 7 ≡ “2”
(this result will be added to the digits of the third period)
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